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3.613 g of a molecular compound (M= 180 g mol^-1) was dissolved in 25.00 g of...

3.613 g of a molecular compound (M= 180 g mol^-1) was dissolved in 25.00 g of water. What is the expected change in freezing point of the water?

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Answer #1

molality    = W*1000/G.M.Wt * weight of solvent in g

              = 3.613*1000/180*25   = 0.802m

   Kf      = 1.86C0/m

     i     = 1 for non eletrolyte

Tf     = i*m*Kf

            = 1*0.802*1.86

              = 1.490C  

change in freezing point of the water = 1.490C  

         

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