Question

If the Ka of a monoprotic weak acid is 1.6

Answer 1

pH= -Log(H+)

u don't have H+ directly but u have ka and molarity i.e concentration so we use formula
H+= under root ( or roof of) Ka.C ----(ka multiply C)

H+= 8 * 10 raise to -4 or 0.0008

pH= -log(0.0008)
= -(-3.0969)
the Ph is= 3.0969

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while doing ionic u need this formulas for calculate Ph..
H+ = alpha ( degree of ionisation or dissociation) . C
= ?.C --- thats how we call this
K = ?(square).C
and the one which i mentioned before