What is the pH at 25°C of a solution that results from mixing equal volumes of a 0.05 M solution of acetic acid and a 0.025 M solution of sodium hydroxide
when acetic acid and NaOH mixed then reaction is
CH3COOH + NaOH ..............> CH3COONa + H2O
let x L of of NaOH and x L of CH3COOH is mixed.
so x L of 0.05 M acetic acid = x * 0.05 = 0.05 x mole.
x L of 0.025 M NaOH =x * 0.025 = 0.025 x mole.
moles of salt = 0.025 x mole.
moles of acid = (0.05x - 0.025x) = 0.025x mole.
PKa of acetic acid = 4.74
Resulting solution is buffer solution.
Henderson equation is
PH = PKa + log [salt] / [acid]
PH = 4.74 + log (0.025x / 0.025x)
PH = 4.74 + log (1)
PH = 4.74
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