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Assuming 100% dissociation, calculate the freezing point (Tf) and boiling point (Tb) of 3.26 m Na2SO4(aq)....

Assuming 100% dissociation, calculate the freezing point (Tf) and boiling point (Tb) of 3.26 m Na2SO4(aq).

Tf= ∘C

Tb= ∘C

Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
Solvent Formula Kf value*

(°C/m)

Normal freezing

point (°C)

 Kb value

(°C/m)

Normal boiling

point (°C)
water H2O 1.86 0.00 0.512 100.00
benzene C6H6 5.12 5.49 2.53 80.1
cyclohexane C6H12 20.8 6.59 2.92 80.7
ethanol C2H6O 1.99 –117.3 1.22 78.4
carbon
tetrachloride		 CCl4 29.8 –22.9 5.03 76.8
camphor C10H16O 37.8 176
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