4 KO2 + 2 CO2 -------------> 2 K2CO3 + 3 O2
284.4 g 88.02 g 276.411 g 96 g
25.00 g 11.00 g
284.4 g KO2 --------------> 88.02 g CO2
25.0 g KO2 ----------------> ??
mass of CO2 needed = 25.00 x 88.02 / 284.4
= 7.737 g
so CO2 is excess .
here limiting reagent is KO2
284.4 g KO2 --------------> 96 g O2
25.0 g KO2 ----------------> ??
mass of CO2 produced = 25.0 x 96 / 284.4
= 8.439 g
mass of CO2 produced = 8.439 g
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