Question

There is an aqueous solution containing 0.0015 M Na2SO4 and 0.0026 M AlCl3. (Ignore the dissociation...

There is an aqueous solution containing 0.0015 M Na2SO4 and 0.0026 M AlCl3. (Ignore the dissociation of water.) (a) Calculate the ionic strength of this solution. (b) Calculate the activity coefficients of all anions in this solution.

Homework Answers

Answer #1

(a)

Ionic strength is calculated using the formula:

I = 0.5*(ci*zi2)

Here ci is the concentration of the 'i'th species, and zi is its oxidation number

Here we have four species Na+, SO42-, Al3+ and Cl-, with conc. values 0.003, 0.0015, 0.0026 and 0.0078 M respectively, and z values as +1, -2, +3, -1 respectively.

Putting values and solving we get:

I = 0.020

(b)

At this ionic strength value, the activity coefficients for anions are calculated using the Debye Huckel relation which is as follows:

log f = -0.51*z2*I0.5/(1+I0.5)

Here f is the activity coefficient.

Putting values and solving we get:

fsulphate anion = 0.572

fchloride anion = 0.865

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