Question

i feel very confuse about the calculation... i have been sitting in front of the lab...


i feel very confuse about the calculation...
i have been sitting in front of the lab report for more than one hour..
can someone help me :-[?
the question is to demination of the concentration of NaOH and Na2CO3 in a NaOH/Na2Co3 mixture (method of double indicators)
i titre the mixture with a standardized HCl(0.1M) (standardized by NaOH)
here are the reaction involved:
NaOH + HCl -->NaCl + H2O
Na2CO3 + HCl --> NaHCO3 + NaCl 1st-end-pt
NaHCO3 + HCl --> NaCl + H2O + CO2 2nd-end-pt
values
Part b : Double indicator method
1st end-pt : 16.875cm3 of HCl used
2nd end-pt : 6.2cm3 of HCl used
16.875 - 6.2 = 10.675cm3 of HCl used in 2nd end-pt
calculate the concentration of NaOH and Na2CO3
thanks.

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