Question

In a typical person, the level of blood glucose is about 85mg/100mL of blood. If an...

In a typical person, the level of blood glucose is about 85mg/100mL of blood. If an average body contains about 11 pints of blood, how many pounds of glucose are present? 1 Pound= 454 grams 1dL= .2113 pints

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Given that 100 mL of blood contain 85 mg glucose. To find amount of glucose in pounds present in the 11 pints, we have to convert the given details to proper units.

Amount of glucose present in the 11 pints of blood is 0.0097 (around 0.01 pounds)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
a. Nonpregnant women have an average fasting blood glucose level of about 80 mg/100mL of blood....
a. Nonpregnant women have an average fasting blood glucose level of about 80 mg/100mL of blood. Researchers want to determine if pregnancy causes a change in blood glucose level. They take a random sample of 25 third trimester women and find their average fasting blood glucose level is 75 mg/100mL with sample standard deviation of 9.68. Find 90% and 95% confidence intervals for average fasting blood glucose level of third trimester women. b. Repeat the previous question, but this time...
The body stores carbohydrates as glycogen in the liver and muscles. When a person stops eating...
The body stores carbohydrates as glycogen in the liver and muscles. When a person stops eating carbohydrates, blood glucose is maintained primarily by using glycogen stored in the liver. Once this is gone, the body will begin catabolizing muscle into glucose. The liver can store 200.0 g glycogen, and exactly 1 g glycogen can be converted to 1 g glucose by the body when necessary. The average body contains 5.000 L of blood and can usually maintain a blood glucose...
A typical glass of wine contains about 1 grams of alcohol. Consider a 118-pound woman, with...
A typical glass of wine contains about 1 grams of alcohol. Consider a 118-pound woman, with approximately 6 liters (6000 millimeters) of blood, who drinks two glasses of wine.Complete parts (a) and (b) below. a. If all the alcohol were immediately absorbed into her bloodstream, What would her blood alcohol content be? Explain why it is fortunate that, in reality, the alcohol is not absorbed immediately. b. Again assume all the alcohol is absorbed immediately, but now assume her body...
1. According to the Joslin Clinic, healthy individuals without diabetes should have a blood glucose level...
1. According to the Joslin Clinic, healthy individuals without diabetes should have a blood glucose level of no more than 100 mg dL−1 after awaking, before breakfast. What is the molarity of glucose in the blood of a healthy individual whose blood glucose level is 100 mg dL−1? 2. One index of toxicity is the LD50, the amount of substance which, when administered to a group of subject, will kill 50% of that group. (LD50 stands for lethal dose of...
A normal blood glucose level in dogs is 3.3 - 6.1 mmol/L. This dog shows a...
A normal blood glucose level in dogs is 3.3 - 6.1 mmol/L. This dog shows a blood glucose level of 1.6 mmol/L and is depressed, ataxic, and disoriented. Treatment of acute hypoglycemia consists of an IV bolus of 1 - 2 mL/kg of 50% dextrose (D-glucose) via central venous line or 2 - 4 mL/kg of 25% dextrose via peripheral vein over three minutes. -How would you make 50 mL of 25% dextrose from a sterile 50% dextrose solution and...
Jeff's body contains about 5.38 L of blood that has a density of 1060 kg/m 3...
Jeff's body contains about 5.38 L of blood that has a density of 1060 kg/m 3 . Approximately 45.0 % (by mass) of the blood is cells and the rest is plasma. The density of blood cells is approximately 1125 kg/m 3 , and about 1 % of the cells are white blood cells, the rest being red blood cells. The red blood cells are about 7.50 μ m across (modeled as spheres). What is the mass of the blood...
Jeff's body contains about 5.26 L of blood that has a density of 1060 kg/m3. Approximately...
Jeff's body contains about 5.26 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells and the rest is plasma. The density of blood cells is approximately 1125 kg/m3, and about 1% of the cells are white blood cells, the rest being red blood cells. The red blood cells are about 7.50μm across (modeled as spheres). What is the mass of the blood mblood in Jeff's body? mblood=_______ kg Approximately how...
The glycemic index alone is insufficient to explain the effect of food consumption on blood glucose...
The glycemic index alone is insufficient to explain the effect of food consumption on blood glucose levels. We often consume carbohydrates with other nutrients (proteins and/or fats) which can alter digestion rates and glucose absorption rates. Many other factors can affect the rate of food processing and absorption—and thus blood glucose levels—as well. Consider one of the following factors and design a simple but conclusive experiment that would assess how that factor would affect blood glucose levels. • Cooking food...
At body temperature (37°C), blood has an osmotic pressure of about 8.2atm. To match this pressure...
At body temperature (37°C), blood has an osmotic pressure of about 8.2atm. To match this pressure with NaCl solution (saline), how many grams of NaCl should you dissolve in water for 1.00L of solution?
In a study on the effect of diet on blood glucose levels, 26 subjects were assigned,...
In a study on the effect of diet on blood glucose levels, 26 subjects were assigned, at random, to one of four diets. The recorded blood glucose levels are in mmol per liter. Diet A B C D 6.0 6.5 7.5 7.5 4.5 5.3 8.0 7.0 6.3 5.8 7.3 6.8 5.8 6.3 6.3 5.8 5.5 5.0 7.8 7.8 6.0 8.3 6.3 5.0 7.3 7.0 A-How many groups? Calculate the dfb and dfw?                                B-The H0 there are no difference in...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT