Question

8.51 mol of SO2, 7.65 mol of O2 and 4.92 mol of SO3 are placed in a 4.4L reaction vessel at a certain temperature.

2SO2(g)+O2(g)=2SO3(g)

What is the reaction quotient (Q) and which way will the reaction shift if the Kc value is 0.38

Answer 1

Gven equation is

2 SO2(g) + O2(g) = 2 SO3(g)

Given 8.51 mol SO2, 7.65 mol of O2, 4.92 mol SO3 and volume=4.4 L

Now find the molarity of each gas,

[SO2]= 8.51 mol/ 4.4 L=1.93 M

[O2]= 7.65 mol/4.4 L=1.74 M

[SO3]= 4.92 mol/4.4 L=1.12 M

Reaction quotient Q=[SO3]²/[SO2]²[O2]

Q=[1.12]²/[1.93]²[1.74]=0.1935.

Given Kc=0.38

Kc=[SO3]²/[SO2]²[O2]=0.38, represents reactants concentration is more than product concentarion. So the

equilibrium shifted to right side of reaction.