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Calculate the [H3O+] and the concentrations of A- and HA in the 1/2 neutralized solution. (Note...

Calculate the [H3O+] and the concentrations of A- and HA in the 1/2 neutralized solution. (Note that [H3O+} does not equal [A-]).

The mass of acetic acid solution is 30.01 g

Volume of the NaOH added to 1/2 neutralize the acetic acid is 6.2 mL

Measured pH of 1/2 neutralized solution is 4.8

The concentration of standardization NaOH titration is 0.09755 mol/L

The average pH value is 4.8

PKa 4.8

Ka 1.58x10^-5

** In my notes it says that the [HA]=[A-]** This is where I am getting confused.

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