Question

You just spilled 94.66 mL of 1.19 M sulfuric acid on your lab bench and need...

You just spilled 94.66 mL of 1.19 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to you there is a small jar labeled “18 g sodium bicarbonate”.

Will this be enough sodium bicarbonate to neutralize the spilled sulfuric acid?

Enter Y or N

If no, how many more grams are required? If yes, how many extra grams do you have remaining?

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Homework Answers

Answer #1

H2SO4 + Na2CO3 = Na2SO4 + CO2 + H2O

MOLES OF H2SO4 = molarity * volume (in L)

= 1.19 * ( 94.66 * 10^-3 )

= 0.1126

moles of Na2CO3 = mass / molar mass

= 18 / 106

= 0.1698

mole ratio should be 1:1 but here amount of Na2CO3 is slightly more than H2SO4.

yes it more than enough to clean.

remaining moles of Na2CO3 = 0.1698 - 0.1126 = 0.0572

mass of Na2CO3 = moles * molar mass

= 0.0572 * 106

= 6.0632 grams

any question please comment

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