If it takes 3.36 x 10^-9 J of energy to eject an electron from the surface of a certain metal, calculate the frequency of this energy and the longest possible wavelenght in nm.
Energy and frequency of a photon are related by E = hν, where h
is Planck's constant (6.626 x 10^(-34) J s) and ν is the frequency
of the photon. We have:
3.36 x 10-19 J = 6.626 x 10-34 Js x ν
ν = 3.36 x 10-19 J / 6.626 x 10-34 Js
ν = 5.07 x 1024 Hz.
On the other hand, wavelength and frequency of electromagnetic radiation are related by c = λν, where c is the speed of light (3.00 x 108 m/s).
So λ = c/ν = (3.00 x 108 m/s) / 5.07 x 1024 Hz. = 5.91x 10-17m = 59.1x10-18 = 59.1 a.m
( a = atto = 10-18 )
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