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# Inorganic questions--please show work and only answer if you truly understand it: Please show all work...

Inorganic questions--please show work and only answer if you truly understand it:

Please show all work and answers on this page if at all possible.

5. Arrange the following solutions in order of decreasing freezing point, and explain your reasoning: 0.50 m HCl, 0.50 m glucose, 0.50 m acetic acid.

6. The alcohol content of hard liquor is normally given in terms of the “proof”, which is defined as twice the percentage by volume of ethanol (C2H­5OH) present. Calculate the number of grams of alcohol present in a glass of of 75-proof gin (assume a 4 oz glass). The density of ethanol is 0.798 g/mL.

7. You find a solution on the shelf that is labeled 30% NH3 (aq). The density of the solution is 0.982 g/mL. Calculate the following:

a) mole fraction of ammonia = ____________

b) molality of ammonia = ____________

c) molarity of ammonia = ____________

8. Adrenaline is the hormone that triggers release of extra glucose molecules in times of stress or emergency. A solution of 0.64 g of adrenaline in 36.0 g of CCl4 causes an elevation of 0.49˚C in the boiling point. Given that the kb for CCl4 is 5.02 C/m, what is the molecular mass of adrenaline.

9.   The Henry's Law constant for the solubility of nitrogen in water is 6.40x10-4 M/atm at 25.0 Celsius. At 570 torr, how many grams of N2 can be dissolved in 250 L of water at 25.0 degrees Celsius

10.    What is the osmotic pressure of a 1.36 M aqueous solution of urea [(NH2)2CO)] at 22.0˚C ?

#### Homework Answers

Answer #1

5) The freezing point will be depressed most by the solution that contains the most
solute particles.

Classify each solute as a strong electrolyte, a weak electrolyte, or a
nonelectrolyte.

Here, three solutions have the same concentration (0.50m), so comparing the solutions  is straight forward.

HCl is a strong electrolyte, so under ideal conditions it will
completely dissociate into two particles per molecule.
HCl. ------> H+ + Cl-

Acetic acid is a weak electrolyte, so it will only dissociate to a small extent.

CH3COOH <-----> CH3COO- + H+

Glucose is a nonelectrolyte, so glucose molecules remain as glucose molecules in solution.

for these solutions, the order in which the
freezing points become lower is:
0.50 m glucose > 0.50 m acetic acid > 0.50 m HCl
The HCl solution will have the lowest freezing point

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