Question

If you start with 0.173 g of anisole and end up with 0.105 g of o-bromoanisole, what is the percent yield of o-bromoanisole?

Answer 1

mass of anisole = 0.173 g

moles of anisole = 0.173 / 107.13 = 1.615 x 10^-3 mol

1 mol anisole gives --------------> 1 mol o-bromoanisole

1.615 x 10^-3 mol ---------------->   1.615 x 10^-3 mol o-bromoanisole

mass of o-bromoanisole = 1.615 x 10^-3 x 187.036

                                      = 0.302 g

percent yield = (actual / theoretical ) x 100

                     = (0.105 / 0.302 ) x 100

                    = 34.77 %