The N enzyme and its two substrates, D and W
a. Use the following datat and the attached graph paper to determine Km and Vmax for the N hydrolysis of its D substrate and of its W substrate.
b. Choose ONE substrate and use the following data to determine Km and Vmax from a linear graph, then calculate the Kcat and Kcat/Km if the enzyme concentration is 1.5ng/microliter.
c. For which of these two substrates does the N enzyme have least affinity?
[D] (mM) | Vo (nmoles/min) | [W] (mM) | Vo (nmoles/min) |
2.1 | 2 | 1.3 | 1 |
4.2 | 3.4 | 2.6 | 1.7 |
8.4 | 5.5 | 5.2 | 2.8 |
16.8 | 8.5 | 10.4 | 4.3 |
25 | 10 | 15 | 5 |
50 | 11 | 30 | 5.5 |
From the given data
Drawn below are two plots doe D and W
a. for D
Km = 80 mM
Vmax = 2.07 nmol/min
for W
Km = 33.33 mM
Vmax = 1.0367 nmol/min
b. For D
Kcat = Vmax/[Et]
= 2.07/1.5
= 1.38
Kcat/Km = 1.38/80 x 10^6
= 1.725 x 10^-8
Plots
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