Calculate the energy of the red light emmitted by a neon atom with wavelength of 680 nm.
a) 1 x 10
b) J
The red light will consist of photons and they only carry the energy of light.
According to Planck's-Einstein's relation,
E=h.
where E= energy of photon,
h= Planck's constant = 6.626*10-34 J.s
= frequency of the light
Also, = c/
where c= speed of light = 3*108 m/s
& = wavelength of light = 680 nm (given)
1 nm =10-9 m
So, = 680*10-9 m
putting this in above expression,
E=(h.c)/ = (6.626*10-34)*(3*108)/(680*10-9) = 2.9*10-19 J
Thus energy of light is 2.9*10-19 J
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