What is the buffer-component concentration ratio, [Pr - ]/[HPr], of a buffer that has a pH of 5.01 (Ka of HPr = 1.3 ✕ 10-5)?
Pka = -logka
= -log1.3*10-5
= 4.886
PH = PKa + log[Pr-]/[HPr]
5.01 = 4.886 + log[Pr-]/[HPr]
log[Pr-]/[HPr] = 5.01-4.886
log[Pr-]/[HPr] = 0.124
[Pr-]/[HPr] = 100.124
[Pr-]/[HPr] = 1.3304/1 >>>> answer
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