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You add 0.0100 g of solid Na2CO3 to 1.000 L of a 1.00 x 10-5 M...

You add 0.0100 g of solid Na2CO3 to 1.000 L of a 1.00 x 10-5 M aqueous solution of Ba(NO3)2. Will a precipitate of BaCO3 (s) form?

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Answer #1

    Na2CO3(aq) + Ba(NO3)2(aq) ----> BaCO3(s) + 2NaNO3(aq)

   concentration of Ba^2+ions = 1.00 *10^-5 M

   concentration of CO3^2- ions = Na2CO3 = (0.01/106)*(1/1) = 9.434*10^-5 M

Qsp of BaCO3 = [Ba^2+][co3^2-]

               = (1.00 *10^-5)(9.434*10^-5)

               = 9.434*10^-10

   ksp of BaCO3 = 5.1*10^-9

Qsp < Ksp. so that no precipitation takes place.

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