Question

At 25 ∘C, the osmotic pressure of a solution of the salt XY is 47.5 torr . What is the solubility product of XY at 25 ∘C?

Answer #1

T = 25 + 273 = 298K

osmotic pressure P = 47.5 torr = 47.5 /760 = 0.0625 atm

S = 0.0821 L-atm / mol K

for XY

vanthoff factor i = 2

**P = i M S T**

0.0625 = 2 x M x 0.0821 x 298

M = 1.278 x 10^-3 molar

solubility = 1.278 x 10^-3 M

XY -------------------> X+ + Y-

S S

Ksp = [X+][Y-]

Ksp = S^2

Ksp = (1.278 x 10^-3)^2

Ksp = 1.63 x 10^-6

**solubility product = 1.63 x 10^-6**

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