Question

How many equivalents of methanol are you using relative to the vegetable oil in an experiment assuming you are using 0.5 mL of vegetable oil and 1 mL of methanol?

vegetable oil (MW: 883 g/mol, d: 0.875 g/mL)

Answer 1

Weight of Vegitable oil = 0.5 x 0.875 = 0.4375

Number of moles of Vegitable oil = (Weight / MW) 0.4375 / 883 = 0.000495 mol

This mole is considered as "x"

Number of moles of methanol = 1 / 32 = 0.03125

This is considered as "y"

to find nuber of equivelent used is = y / x

so, 0.03125 / 0.000495 = 63.13

so 1 : 63.13 ratio is using

to confirm it we can calculate again by normal calculation

number of moles of vegitable oil = 0.000495 = 1 equivalent

methanol 63.13 equivalent, means 0.000495 x 63.13 = 0.03125

amount of methanol is = 0.03125 x 32 (MW) = 1