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A 5g sample of lithium is reacted with 5g of fluorine to form lithium fluoride: 2Li...

A 5g sample of lithium is reacted with 5g of fluorine to form lithium fluoride: 2Li + F2 → 2LiF. After the reaction is complete, what will be present?

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Answer #1

Number of moles of Lithium = 5/7 = 0.714 moles

Number of moles of Flourine = 5/38 = 0.1315 moles

1 mole of Flourine will react with 2 moles of Li, hence the flourine is the limiiting reagent

1 mole of flourine will give 2 moles of LiF

Hence moles of LiF formed = 0.1315 * 2 = 0.2630 moles

Mass of LiF formed = 0.2630 * 26 = 6.838 gms

Mass of Lithium remaining = 10 - 6.838 = 3.162 gms

Hence there will be only lithium floride and lithium will be present in the reaction after the completion

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