Solutions containing aqueous barium nitrate and aquueous zinc sulfate are combined to yield a precipitate of barium sulfate, if the original solution contained 3.5 g of barium nitrate, calculate the mass of precipitate that complete titration should produce.
A.2.67 g
B. 3.12 g
C. 4.44 g
D. 2.4 g
The reaction is
Ba(NO3)2(aq) + ZnSO4(aq) BaSO4(s) + Zn(NO3)2(aq)
molar mass of Ba(NO3)2 = 261.337 gm/mole
molar mass of BaSO4 = 233.43 gm/mol
according to reaction 1 mole of Ba(NO3)2 produce 1 mole precipitate of BaSO4 that mean 261.337 gm of Ba(NO3)2 produce 233.43 gm of BaSO4 then 3.5 gm of Ba(NO3)2 produce =
3.5 233.43 / 261.337 = 3.12 gm of BaSO4
Answer - B . 3.12 g
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