Question

During the initial stages of the following reaction the rate law is Rate = k[H2][Br2]½. H2(g)...

During the initial stages of the following reaction the rate law is
Rate = k[H2][Br2]½.
H2(g) + Br2(g) → 2 HBr(g)
What is the order of the reaction with respect to each component and the overall order?

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Answer #1

Rate = k[H2][Br2]½.
H2(g) + Br2(g) → 2 HBr(g)

the order with respect H2= 1

the order with respect Br2= 1/2

overall order of areaction = order with respect H2+ order with respect Br2

                                    = 1+1/2

                                 = 3/2

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