During the initial stages of the following reaction the rate law
is
Rate = k[H2][Br2]½.
H2(g) + Br2(g) → 2 HBr(g)
What is the order of the reaction with respect to each component
and the overall order?
Rate = k[H2][Br2]½.
H2(g) + Br2(g) → 2 HBr(g)
the order with respect H2= 1
the order with respect Br2= 1/2
overall order of areaction = order with respect H2+ order with respect Br2
= 1+1/2
= 3/2
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