Question

At 25 °C only 0.0590 mol of the generic salt AB is soluble in 1.00 L...

At 25 °C only 0.0590 mol of the generic salt AB is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C?

Homework Answers

Answer #1

solubility of AB = no of moles/volume in L

                          = 0.059/1 = 0.059M

AB-------------> A+ + B-

                        S    S

Ksp   = [A+][B-]

          = S*S

          = 0.059*0.059 = 0.003481 >>>>>answer

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