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The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...

The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life.

Part A What is the half-life of a first-order reaction with a rate constant of 6.40×10−4 s−1?

Part B What is the rate constant of a first-order reaction that takes 522 seconds for the reactant concentration to drop to half of its initial value?

Part C A certain first-order reaction has a rate constant of 3.40×10−3 s−1. How long will it take for the reactant concentration to drop to 18 of its initial value?

Please show your work. Thank you!

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