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The space shuttle orbiter utilizes the oxidation of methyl hydrazine by dinitrogentetroxide for propulsion. The reaction...

The space shuttle orbiter utilizes the oxidation of methyl hydrazine by dinitrogentetroxide for propulsion. The reaction is 4 N2H3CH3(l) + 5 N2O4(l) ↔ 9 N2(g) + 12 H2O(g) + 4 CO2(g) What is ΔH°rxn for this reaction (in kilojoules)? N2H3CH3(l) ΔHfo = 54 kJ/mol. N2O4(l) ΔHfo = -19.5 kJ/mol. H2O(g) ΔHfo = -241.8 kJ/mol. CO2(g) ΔHfo = -393.5 kJ/mol.

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Answer #1

we have:

Hof(N2H3CH3(l)) = 54.0 KJ/mol

Hof(N2O4(l)) = -19.5 KJ/mol

Hof(CO2(g)) = -393.5 KJ/mol

Hof(H2O(g)) = -241.8 KJ/mol

we have the Balanced chemical equation as:

4 N2H3CH3(l) + 5 N2O4(l) ---> 9 N2(g) + 4 CO2(g) + 12 H2O(g)

deltaHo rxn = 9*Hof(N2(g)) + 4*Hof(CO2(g)) + 12*Hof(H2O(g)) - 4*Hof( N2H3CH3(l)) - 5*Hof(N2O4(l))

deltaHo rxn = 9*0 + 4*(-393.5) + 12*(-241.8) - 4*(54.0) - 5*(-19.5)

deltaHo rxn = -4594.1 KJ

Answer: -4594.1 KJ

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