Question

There are 200mL of .30M HCl in a solution. How many mL of 0.04 NaOH are needed to neutralize the solution.

Answer 1

Molarity of HCl = number of moles of HCl / volume of solution in L

0.30 M = number of moles of HCl / 0.200 L

Number of moles of HCl = 0.3*0.200 = 0.06 mole

Balanced eqaution is

HCl + NaOH -----> NaCl + H2O

from the balanced equation we can say that

1 mole of HCl requires 1 mole of NaOH so

0.06 mole of HCl will require 0.06 mole of NaOH

Molarity of NaOH = number of moles of NaOH / volume of solution in L

0.04M = 0.06 / volume of solution in L

volume of solution in L = 1.5 L

1 L = 1000 mL

1.5 L = 1500 mL

therefore, the volume of NaOH needed will be 1500 mL