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Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many...

Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many liters of H2 would be formed at 558 mm Hg and 17 ∘C if 26.0 g of zinc was allowed to react? Part B How many grams of zinc would you start with if you wanted to prepare 5.85 L of H2 at 208 mm Hg and 29.5 ∘C?

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