Question

A solution contains 23% A by mass and 42% B by mole

a) Caculate the mass of A in 225 Kg of solution

b) Calculate the mass flow rate of A in a stream flowing at 53 pound mass per hour

c) Calculate the molar flow rate of B in a stream flowing at 1000 moles per minute

d) Calculate the total solution flow rate corresponding to a molar flow rate of 28 kmoles B per second

e) Calculate the mass of the solution that contains 300 pound mass of A

Answer 1

A)

mass of A in total mass = 225k

mass of A = %A / 100% * Mt = 23/100*225 = 51.75 kg of A

b) Calculate the mass flow rate of A in a stream flowing at 53 pound mass per hour

0.23 lb of A / toal lb * 53 total Lb / hours = 12.19 lb of A /hour

c) Calculate the molar flow rate of B in a stream flowing at 1000 moles per minute

xb = 42/100 = 0.42

so...

0.42*1000 = 420 moles of B per min

d) Calculate the total solution flow rate corresponding to a molar flow rate of 28 kmoles B per second

kmol of B = 28

so..

xb = 0.42

then

28/0.42 = 66.666 total kmol / s

e) Calculate the mass of the solution that contains 300 pound mass of A

xa = 0.23

mass of A = 300 lb

total mass = ?

total mass = 300/0.23 = 1304.34 lb of A