Question

How many milliliters of 0.100 M NaOH are required to neutralize the following solutions? (a) 7.00 mL of 0.0500 M HCL (b) 40.00 mL of 0.126 M HNO3 (c) 65.5 mL of 0.215 M H2SO4

Answer 1

a) NaOH + HCl -------> NaCl + H₂O

1 equiv of NaOH is needed to neutralise 1 equivalent HCl

M1 V1 = M2 V2

0.1 x V1 = 0.05 x 7 = 3.5 mL (of 0.1 M NaOH is needed

b) NaOH + HNO₃ -------> NaNO₃ + H₂O

according to the above equation

1 equiv of NaOH is needed to neutralise 1 equivalent HNO₃

M1 V1 = M2 V2

0.1 x V1 = 0.126 x 40 = 50.4 mL

c) 2 NaOH + H₂SO₄ -------> Na₂SO₄ + 2 H₂O

according to the above equation

2 equiv of NaOH is needed to neutralise 1 equivalent of H₂SO₄

M1 V1 = M2 V2

0.1 x V1 = 0.215 x 65.5 = 140.825 mL

But we need 2 equiv of NaOH to neutralise 1 equivalent of H₂SO_4, so 281.65 mL of NaOH is needed