For the titration of 30.0 mL of 0.250
M acetic acid with 0.200 M
sodium hydroxide, determine the pH when:
(a) 30.0 mL of base has been added.
(b) 37.5 mL of base has been added.
(c) 45.0 mL of base has been added.
(the answers must have the right significant figures)
pKa of acetic acid = 4.74
HA + NaOH ---------------> NaA- + H2O
30x0.25 0 0 0 initial mmoles
1) - 30x0.2 - - change
1.5 0 6 - after
buffer osolution . whose pH is given By Hendersen equation
pH = pKa + log [conjugate base]/[acid]
= 4.74 + log 6/1.5
=5.3420
b) - 37.5x 0.2 - - change
0 0 7.5 - after
The solution has only salt whose pH is given by
pH = 1/2[pKw +pKa +logC]
= 1/2 [ 14 +4.74 + log 7.5/67.5]
= 8.8928
c) - 45x0.2 - - change
0 1.5 7.5 - mmoles after reaction
the solution has a strong base and a salt
[OH-] = 1.5/75=0.02M
pH = 14 - pOH
= 14-[-log{OH-]}
= 12.3010
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