Question

An experiment was performed to determine the solubility and the solubility product constant of gallic acid,...

An experiment was performed to determine the solubility and the solubility product constant of gallic acid, a monoprotic organic (gmm = 170.12). The equilibrium involved is C6H5O3COOH(s) ------C6H5O3COO-(aq) + H+(aq) Titrations using 1.14 x 10^-1M NaOH were performed, and the following data was obtained Determinations 1, 2, 3 temperature of solution 20.2 20.4 20.1 volume of acid solution titrated, mL 25.00 22.00 20.10 volume of NaOH solution, mL 14.61 13.02 11.73 Calculate: number of moles of NaOH used _____ _____ ______ number of moles of H+ titrated _____ _____ ______ [H+} in acid solutin _____ _____ ______ Ksp _____ _____ ______ average Ksp ____ solubility of acide in g per 100 mL _____ chemistry handbook value for solubility at 20 degrees 1.15 per 100 mL

Homework Answers

Answer #1

An experiment was performed to determine the solubility and the solubility product constant of gallic acid, a monoprotic organic (gmm = 170.12).

The equilibrium involved is

C6H5O3COOH(s) ------C6H5O3COO-(aq) + H+(aq)

Titrations using 1.14 x 10-1M NaOH were performed,

Determination Temperature of solution Volume of acid solution titrated Volume of NaOH solution
1

20.2

25.00 mL 14.61 mL
2

20.4

22.00 mL

13.02 mL

3

20.1

20.10 mL 11.73 mL

Calculate:

Number of moles of NaOH used _____ _____ ______

Number of moles of H+ titrated _____ _____ ______

[H+] in acid solutin _____ _____ ______

Ksp _____ _____ ______

Average Ksp ____

Solubility of acide in g per 100 mL _____

chemistry handbook value for solubility at 20 degrees 1.15 per 100 mL

Number of moles of NaOH used:

Determination 1

Determination 2

Determination 3

Number of moles of H+ titrated:

Determination 1

Determination 2

Determination 3

[H+] in acid solution

Determination 1

Determination 2

Determination 3

Ksp

Determination 1

Determination 2

Determination 3

Average Ksp

Solubility of acid in g per 100 mL

1) The molar solubility of C6H5O3COOH(s)

C6H5O3COOH(s) ------C6H5O3COO-(aq) + H+(aq)

You want to know the solubility on acid in g per 100 ml:

in 100ml:

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