An experiment was performed to determine the solubility and the solubility product constant of gallic acid, a monoprotic organic (gmm = 170.12).
The equilibrium involved is
C6H5O3COOH(s) ------C6H5O3COO-(aq) + H+(aq)
Titrations using 1.14 x 10-1M NaOH were performed,
Determination | Temperature of solution | Volume of acid solution titrated | Volume of NaOH solution |
1 |
20.2 |
25.00 mL | 14.61 mL |
2 |
20.4 |
22.00 mL |
13.02 mL |
3 |
20.1 |
20.10 mL | 11.73 mL |
Calculate:
Number of moles of NaOH used _____ _____ ______
Number of moles of H+ titrated _____ _____ ______
[H+] in acid solutin _____ _____ ______
Ksp _____ _____ ______
Average Ksp ____
Solubility of acide in g per 100 mL _____
chemistry handbook value for solubility at 20 degrees 1.15 per 100 mL
Number of moles of NaOH used:
Determination 1
Determination 2
Determination 3
Number of moles of H+ titrated:
Determination 1
Determination 2
Determination 3
[H+] in acid solution
Determination 1
Determination 2
Determination 3
Ksp
Determination 1
Determination 2
Determination 3
Average Ksp
Solubility of acid in g per 100 mL
1) The molar solubility of C6H5O3COOH(s)
C6H5O3COOH(s) ------C6H5O3COO-(aq) + H+(aq)
You want to know the solubility on acid in g per 100 ml:
in 100ml:
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