Question

How many times more energy is there in one photon of an x-ray
with a frequency of 1.00 x 10^{12} s -1 than in one photon
of a radar wave with a frequency of 2.00 x 10^{9} s -1
?

What has more energy, 6.00 moles of photons of light with a frequency of 1.00 x 1012 s -1 or a can of diet pop that has 1.00 Calorie per can? 1.000 Calorie = 4184 Joules

Answer #1

a) energy of photon = hxfrequency where h = Planck's constant =
6.626x 10^{-34} J .sec

Thus energy of photon = 6.626x 10^{-34} J.sec
x 1.00x10^{12} sec^{-1}

= 6.62x10^{-22}J

similarly energy of radar wave = 6.626x 10^{-34} J .sec
x 2.00x10^{9} sec^{-1}

=1.3252x10 ^{-25}J

So energy of X-ray is
6.626x10^{-22}/1.325x10^{-25} times=
5x10^{3} = 5000 times greater than energy of rada wave.

b) energy of a single photon = h x frqueny

= 6.626x 10^{-34} J .sec x 1.00x
10^{12}sec^{-1}

energy of 6 moles of potons = 6x 6.02x10^{23}x6.626x
10^{-34} J .sec x 1.00x 10^{12}sec^{-1}

=2393 J

energy of a can of diet pop = 1.00Cal = 1.00kcal = 4184 J

Thus the energy of diet pop is more tan 6 phtons o light of given frequency.

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