Question

Calculate the work (w) and ΔE^o, in kJ, at 298 K and 1 atm pressure, for the combustion of one mole of C₄H₁₀ (g). First write and balance the equation. The products will be CO₂ (g) and H₂O (g).
The value of ΔH^o for this reaction is -2658.3 kJ/mol.

The value for w in kJ =

The value for ΔE^o ( in kJ) =

Answer 1

     C4H10 (g) + 6.5 O2(g) ---> 4 CO2(g) + 5 H2O(g)

   Dnrxn = no of mole of Products - no of mole of Reactants

         = (4+5) - (1+6.5)

          = 1.5

work done (w) = -DnRT

              = -1.5*8.314*298

              = -3.716 kj

   DH = DU + DnRT

(-2658.3) = x - 3.716

DU = -2654.6 kj