A 295-mL flask contains pure helium at a pressure of 747 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 717 torr.
A.) If the two flasks are connected through a stopcock and the stopcock is opened, what is the partial pressure of helium?
PHe = ??? torr
B.) If the two flasks are connected through a stopcock and the stopcock is opened, what is the partial pressure of argon?
PAr = ??? torr
C.) If the two flasks are connected through a stopcock and the stopcock is opened, what is the total pressure?
Ptotal =?? torr
first consider helium :
initially
pressure = 747
volume = 295 ml
now
both the flasks are connected
no reaction took place
so
amount of helium remians
also
the tempertaure is constant
but
the volume chages
final volume = 295 + 480
final volume = 775 ml
now
PV = nRT
at constant n and T
P1V1 = P2V2
so
747 x 295 = P2 x 775
P2 = 284.34
so
the new partial pressure of helium is 284.34 torr
b) similarly for Argon
P1V1 = P2V2
717 x 480 = P2 x 775
P2 = 444.08
so
the partial pressure of Argon is 444.08 torr
C)
now
total pressure = PHe + PAr
total pressure = 284.34 + 444.08
total pressure = 728.42
so
the total pressure is 728.42 torr
Get Answers For Free
Most questions answered within 1 hours.