Question

Complete the following table by calculating the missing entries and indicating whether the solution is acidic or basic.

Complete the first row.

Express your answer using two significant figures.

[OH−] =

  M  

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Part B

Complete the first row.

Express your answer using two decimal places.

pH =

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Part C

Complete the first row.

Express your answer using two decimal places.

pOH =

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Part D

Complete the first row. Indicate whether the solution is acidic or basic.

Complete the first row. Indicate whether the solution is acidic or basic.

acidic

basic

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Part E

Complete the second row.

Express your answer using two significant figures.

[H+] =

  M  

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Part F

Complete the second row.

Express your answer using two decimal places.

pH =

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Part G

Complete the second row.

Express your answer using two decimal places.

pOH =

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Part H

Complete the second row. Indicate whether the solution is acidic or basic.

Complete the second row. Indicate whether the solution is acidic or basic.

acidic

basic

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Part I

Complete the third row.

Express your answer using two significant figures.

[H+] =

  M  

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Part J

Complete the third row.

Express your answer using two significant figures.

[OH−] =

  M  

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Part K

Complete the third row.

Express your answer using two decimal places.

pOH =

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Part L

Complete the third row. Indicate whether the solution is acidic or basic.

Complete the third row. Indicate whether the solution is acidic or basic.

acidic

basic

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Part M

Complete the fourth row.

Express your answer using two significant figures.

[H+] =

  M  

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Part N

Complete the fourth row.

Express your answer using two significant figures.

[OH−] =

  M  

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Part O

Complete the fourth row.

Express your answer using two decimal places.

pH =

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Part P

Complete the fourth row. Indicate whether the solution is acidic or basic.

Complete the fourth row. Indicate whether the solution is acidic or basic.

acidic

basic

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[H+]	[OH−]	pH	pOH	Acidic or basic?
7.7×10−3M
	3.6×10−10M
		8.28
			5.72

Answer 1

pH= -log [H+], pOH= -log[OH-], pH+POH=14, if pH lies between 0 and 7, the solution is acidic, pH= 7 means the solution is neutral and pH if lies between t and 14, it is basic

given [H+]= 7.7*10^-3M, pH= -log (7.7*10^-3)= 2.11, poH= 14-2.11= 11.89, [OH-]= 10^(-11.89)= 1.288*10-¹²

^{since the pH is 2.11, the solution is acidic}

2^. [OH-]= 3.6*10^-10 , pOH= -log (3.6*10^-10)= 9.44, pH= 14-9.44= 4.56, acidic, [H+]= 2.75*10^-5M

3. pH= 8.28, basic, pOH= 14-8.28= 5.72, [H+]= 10^(-8.28)= 5.25*10-9, [OH-] =10_^(-5.72)= 1.9*10^-6M

4. pH= 5.72, acidic, pOH= 14-5.72= 8.28, [H+]= 10^(-5.72)= 1.9*10-6M, [OH- 10^(-8.28)= 5.25*10^-9

^2.