SOLUTION:
The reaction is iodination of acetone.
CH3COCH3 + I2 + H+ ----------> CH3COCH2I + HI
(A) Rate = - (chane in concentration of I2 / time taken)
chane in concentration of I2 = Final concetration - initial concentratio = (0 - 0.0050) = - 0.005M
t = 230s
Rate = - (chane in concentration of I2 / time taken) = - ( - 0.005 / 230) = 2.173 X 10-5 Ms-1
(B) Rate equation is given as
Rate = k[Acetone]a[I2]b[H+]c
(C) The four unknowns are given below:
1 rate contsant (k), 2. a, 3. b, 4. c
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