Question

colbalt chloride hexahyrate has a formula weight of 237.9g/mol. How much would you use to make...

colbalt chloride hexahyrate has a formula weight of 237.9g/mol. How much would you use to make 0.5 liter of a 0.3 M solution?

Homework Answers

Answer #1

Answer –

We are given, molarity of colbalt chloride hexahyrate = 0.30 M

Volume = 0.5 L

First we need to calculate the moles of colbalt chloride hexahyrate

We know,

Molarity = moles / volume (L)

So, volume (L) = molarity * moles

                          = 0.30 M * 0.50 L

                           = 0.15 moles

Now we are calculated moles of colbalt chloride hexahyrate and we are given molar mass of colbalt chloride hexahyrate,

So mass of colbalt chloride hexahyrate = moles * molar mass

                                                               = 0.15 moles * 237.9 g/mol

                                                                = 35.7 g

So, 35.7 g of colbalt chloride hexahyrate need to use make 0.5 liter of a 0.3 M solution

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
use 16 g of sodium chloride to make a 20% sodium chloride solution. how much water...
use 16 g of sodium chloride to make a 20% sodium chloride solution. how much water is required to make the solution?
How much stock solution would you need to make 50 mL of a 86 mM Potassium...
How much stock solution would you need to make 50 mL of a 86 mM Potassium chloride (KCl) solution, given the stock solution is 1 M?
KCl is an ionic salt with a formula weight of 74.54 g/mole. A 1.417 M (mole/liter)...
KCl is an ionic salt with a formula weight of 74.54 g/mole. A 1.417 M (mole/liter) KCl solution has a density of 1064.5 grams/liter at 20 OC. Use the Molarity and the formula weight to find the mass (g) of salt in one liter. Then, find the mass (g and kg) of water in one liter of the solution.     Determine the molality (m), or moles of salt per kg of water, by dividing the moles of salt in one liter...
How much strontium chloride (SrCl2) is needed to make 100 ml of a 2.0 molar SrCl2...
How much strontium chloride (SrCl2) is needed to make 100 ml of a 2.0 molar SrCl2 solution? MW of strontium = 87.62 g/mol MW of chlorine = 35.45 g/mol
How many grams of sodium succinate (formula weight 140 g/mol) and disodium succinate (formula weight 162...
How many grams of sodium succinate (formula weight 140 g/mol) and disodium succinate (formula weight 162 g/mol) must be added to 1 L of water to produce a solution with pH 6.0 and a total solute concentration of 50 mM? Pka=5.64
SHOW ALL WORK 1. You have a bottle with 1 liter of 90% ethanol. How do...
SHOW ALL WORK 1. You have a bottle with 1 liter of 90% ethanol. How do you make 250 mL of a solution of 50% ethanol? 2. You have a 1 M stock solution of sodium chloride. How do you make 100 mL of a 0.5 M solution of sodium chloride? 3. How many moles of sucrose are in 10 microliters of a 1 M solution of sucrose?
At 20°C, a 2.32 M aqueous solution of ammonium chloride has a density of 1.0344 g/mL....
At 20°C, a 2.32 M aqueous solution of ammonium chloride has a density of 1.0344 g/mL. What is the molality of ammonium chloride in the solution? The formula weight of NH4Cl is 53.50 g/mol. A) 2.55 m B) 0.0449 m C) 2.32 m D) 0.446 m E) 12.00 m
Chlorine in H2O is tested byadding silver ions to make silver(i)chloride which is insoluble. How much...
Chlorine in H2O is tested byadding silver ions to make silver(i)chloride which is insoluble. How much chloride is in a sample of water if it took 20.2ml of a 0.100 M Ag(no3) solution to react all of the chlorine?
You receive the following prescription: Benzalkonium Chloride Solution             240ml Make solution such that when 10ml is...
You receive the following prescription: Benzalkonium Chloride Solution             240ml Make solution such that when 10ml is diluted to a total volume of 1 liter a 1:5000 is produced. Sig: Dilute 10ml to a liter and apply to affected area twice daily How many milliliters of a 17% solution of benzalkonium chloride should be used to compound the prescription? ANSWER IS 28.2ML PLEASE PROVIDE STEP BY STEP THANK YOU
You have 375 mL of a 1.25 M potassium chloride solution, but you need to make...
You have 375 mL of a 1.25 M potassium chloride solution, but you need to make a 0.50 M potassium chloride solution. How many milliliters of water must you add to the original 1.25 M solution to make the 0.50 M potassium chloride solution? Note: Assume the volumes are additive. Anwer should be in mL of water.