colbalt chloride hexahyrate has a formula weight of 237.9g/mol. How much would you use to make 0.5 liter of a 0.3 M solution?
Answer –
We are given, molarity of colbalt chloride hexahyrate = 0.30 M
Volume = 0.5 L
First we need to calculate the moles of colbalt chloride hexahyrate
We know,
Molarity = moles / volume (L)
So, volume (L) = molarity * moles
= 0.30 M * 0.50 L
= 0.15 moles
Now we are calculated moles of colbalt chloride hexahyrate and we are given molar mass of colbalt chloride hexahyrate,
So mass of colbalt chloride hexahyrate = moles * molar mass
= 0.15 moles * 237.9 g/mol
= 35.7 g
So, 35.7 g of colbalt chloride hexahyrate need to use make 0.5 liter of a 0.3 M solution
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