Question

To make an isotonic solution for an IV, the molarity of NaCl in the IV must be the same as the molarity of blood. What is the molarity of NaCl in blood if 0.0342 moles of NaCl are present in 0.24 L of blood?

Answer 1

We know that MOlarity , M = Number of moles of solute / volume of solution in L

Given Number of moles of solute = Number of moles of NaCl = 0.0342 mol

Volume of the solution , V = 0.24 L

Plug the values we get M = 0.0342 mol / 0.24 L

                                      = 0.14 M

Therefore the Molarity of NaCl in blood is 0.14 M