Question

# Write the equilibrium‑constant expression for the reaction A(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq) in terms of [A],[A], [B],[B], [C],[C], and [D],[D],...

Write the equilibrium‑constant expression for the reaction

A(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)

in terms of [A],[A], [B],[B], [C],[C], and [D],[D], as needed.

Note that ?c,Kc, which is sometimes symbolized as ?eq,Keq, denotes that the equilibrium constant is expressed using molar concentrations. For this question, ?cKc means the same thing as ?eq.

Answer:- the equilibrium constant will be:

Keq = [C]2[D]

Solution:-

Write the equilibrium-constant expression for the reaction

A(s)+3B(l)<------->2C(aq)+D(aq)

We can not include pure solids and pure liquids in the equilibrium expression because they exist in nature not in solution so they cant be in equilibrium

So Here A is solid and B is pure liquid So they won't be written in the equilibrium expression

So the equilibrium constant will be:

Keq = [C]2[D]

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