Question

A gaseous mixture contains 433.0 Torr of H2(g), 365.5 Torr of N2(g), and 78.1 Torr of...

A gaseous mixture contains 433.0 Torr of H2(g), 365.5 Torr of N2(g), and 78.1 Torr of Ar(g). Calculate the mole fraction, X, of each of these gases. XH2= , XN2=, XAr=?

Homework Answers

Answer #1

According to dalton's law total pressure of gas is equal to sum of partial pressure exerted by each individual gas

Ptotal = P1 + P2 + P3

Total pressure = 433 + 365.5 + 78.1 = 876.6 torr

we know the formla

Xi = Pi / P where, Xi =mole fraction of indivisual gas, Pi = partial pressure of indivisual gas, P = total pressure of gas mixture

mole fraction of H2 = 433/876.6 = 0.4939

mole fraction of N2 = 365.5.5/876.6 = 0.4169

mole fraction of Ar = 78.1/ 876.6 = 0.08909

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