Question

Can you please show all work and give an explanation.

3) Consider an electrochemical cell based on the reaction:

                2H+ (aq) + Sn (s) → Sn2+ (aq) + H2 (g)

Which of the following actions would change the measured cell potential?

A) increasing the pH in the cathode compartment

B) lowering the pH in the cathode compartment

C) increasing the [Sn2+] in the anode compartment

D) increasing the pressure of hydrogen gas in the cathode compartment

E) Any of the above will change the measure cell potential.

Answer 1

2H+ (aq) + Sn (s) → Sn2+ (aq) + H2 (g)

E = Eo - (0.059/n) log { [Sn²⁺] P_H2 / [H+]²} , P_H2 = pressure of hydrogen gas

E = Eo - [ (0.059/n) log { [Sn²⁺] P_H2 }- (0.059/n) log [H+]² ]

=  Eo - [ (0.059/n) log { [Sn²⁺] P_H2 }- 2 (0.059/n) log [H+] ]

= Eo - [ (0.059/n) log { [Sn²⁺] P_H2 } + 2 (0.059/n) pH ] [ pH = -log [H+] ]

E = Eo - [ (0.059/n) log { [Sn²⁺] P_H2 } + 2 (0.059/n) pH ]

Therefore,

any changes in pH , [Sn²⁺] and pressure of hydrogen gas -would change the measured cell potential.

Therefore,

ans = E