Question

In regards to 2HCl+Na2Cl➡2NaCl+H2O+Co2
1) What volume of 1.00 my HCLO in liters is needed to react completely (with nothing left over) with 0.750 L of 0.400 my Na2CO3?
2) A 549 ml sample of unknown HCLO solution reacts completely with Na2CO3 to form 20.1g CO2. What is the concentration of the HCl solution?

Answer 1

Balanced equation:
2 HCl + Na₂CO₃ = 2 NaCl + H₂O + CO₂

Question 1)

i hope it is 1M HCl needs in Liter

0.750 L of 0.400 my Na2CO3 = 0.75 x 0.4 = 0.3 Moles

0.3 Moles of Na2CO3 needs 0.6 Moles of HCl

Volume of HCl in liters = 0.3 x 1= 0.3 Liter

Hence 0.3 Liter of 1M HCl is need

Question 2

20.1g CO2 = 20.1 /44 = 0.4568 Moles

To produce 0.4568 moles of CO2 we need (0.4568 x2) 0.9136 moles of HCl which shoud be in 549 ml

Hence Volume of the solution = 0.9136 x 1000 /549 = 1.66 M

The concentration of the HCl solution = 1.66 M