Question

In the laboratory you dissolve 19.0 g of chromium(III) acetate in a volumetric flask and add water to a total volume of 375 . mL.

What is the molarity of the solution?  M

Answer 1

Mass of chromium(III) acetate = 19.0 g

Molar mass of chromium(III) acetate = 229.128 g/mol

moles of chromium(III) acetate = mass of chromium(III) acetate / molar mass of chromium(III) acetate

moles of chromium(III) acetate = (19.0 g) / (229.128 g/mol)

moles of chromium(III) acetate = 0.0829 mol

Molarity of chromium(III) acetate = moles of chromium(III) acetate / volume of solution (L)

Molarity of chromium(III) acetate = (0.0829 mol) / (0.375 L)

Molarity of chromium(III) acetate = 0.221 M