Question

Break down the following into: half reactions, oxidizing agent, reducing agent.

2Sr + O2? 2Sr

2Li + H2? 2LiH

2Cs + Br2? 2CsBr

3Mg + N2? Mg3 N2

Answer 1

2Sr + O2 -----> 2SrO

oxidation half reaction = 2Sr ----> 2Sr^+2 + 4e-

Reduction half reaction = O2 + 4e- --------> 2 O^2-

oxidising agent = which involves in reduction = O2

Reducing agent = which involves in oxidation = Sr

2Li + H2 ---> 2LiH

oxidation half reaction = 2Li ----> 2Li^+ + 2e-

Reduction half reaction = H2 + 2e- --------> 2 H^-

oxidising agent = H2

Reducing agent = Li

2Cs + Br2 ---> 2CsBr

oxidation half reaction = 2Cs ----> 2Cs^+ + 2e-

Reduction half reaction = Br2 + 2e- --------> 2 Br^-

oxidising agent = Br2

Reducing agent = Cs

3Mg + N2 ---> Mg3 N2

oxidation half reaction = 3Mg ----> 3Mg^+2 + 6e-

Reduction half reaction = N2 + 6e- --------> 2 N^3-

oxidising agent = N2

Reducing agent = Mg