She does not get high or low ration than the expected.
While combining Mg with oxygen it does so in a definite proportion, so what ever the Mg reacted sofar is in definite ration it does not vary after complete reaction of Mg with Oxygen.
For example:
We have 10 g. of Mg and let us assume only 5 g. of Mg are reacted so far,
2 Mg + O2 ---------> 2 MgO
Accirding to above eqaution,
2*24 g. of Mg needs 32 g. of O2
then, 5 g. of Mg needs 32 * 5 / 48 = 3.33 g. of O2
Mass ratio of Mg to O2 = 5 : 3.33 = 1.50 : 1.00 = 3.00 : 2.00
If we assume that all of the Mg reacts with Oxygen.
then, 10 g.of Mg needs 10 * 32 / 48 = 6.67 g. of O2
Now, the mass ratio of Mg to O2 = 10.0 : 6.67 = 1.50 : 1 = 3.00 : 2.00
SO we got the same.
Because while combining an element with other element it combines in definite proportions.
It is according to Law of definite proportions proposed by Proust.
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