Question

an antigel solution has 40% glycol ethylene(c2h6o2).

volumique mass of antigel : 1.05g/ml

of benzene=1.11g/ml

ofwater=0.998g/ml at 20degrees

find:concentration of etylene glycol

volumique pourcentage of etylenen glycol(gslt/ml solution)*100

molality of etylene glycol

we diluate a solution of 100ml of ethylene in a new solution of 250 ml.what is the volumique percentage of the diluate solution

Answer 1

We have 40% ethylene glycol (mass%) solution

400 g ethylene glycol in 600 g water

Volume of water = 600 g/0.998 g/ml = 601.2 ml = 0.6012 L

moles ethylene glycol = 400 g/62.07 g/mol = 6.44 mol

molality of ethylene glycol solution = 6.44 mol/0.6012 L = 10.71 m

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Total volume of solution = 1000 g/1.05 g/ml = 952.4 ml

molarity of ethylene glycol solution = 6.44 mol/0.9524 L = 6.76 M

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New solution,

100 ml of 40% solution diluted to 250 ml

final % of solution = 40% x 100 ml/250 ml = 16%