Question

27.1 g of solid ethanol (MW = 46.07 g/mol) at -135.0 C (COLD!) is warmed up...

27.1 g of solid ethanol (MW = 46.07 g/mol) at -135.0 C (COLD!) is warmed up to room temperature (23.0 C). Here are some relevant physical data: Phase Cs (J/gC) Phase change temperature and enthalpy Gas 1.70 J/gC boiling pt: 78.4 C; Hvap: 38.6.7 kJ/mol Liquid 2.44 J/gC freezing pt: -114.1 C; Hfus: 4.9 kJ/mol Solid 2.42 J/gC a) What physical state will this sample of ethanol be at 23.0 C? _________________

b) Calculate the total energy (in kJ) required in the process described above.   

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