Question

PART A) A sample of metal at a known hot temperature is placed in to a calorimeter containing water of known mass and known initial temperature. The temperature of the water rises and the final temperature of the water is recorded. What equation is used to calculate the amount of heat the calorimeter water absorbed?

PART B) How do you deermine the amount of heat lost by the metal if you know the amount of heat gained by the calorimeter water?

Part C) What equation is used to calculate the specific heat of the metal if you now know the amount of heat lost by the metal?

* PLEASE EXPLAIN IN DETAIL

Answer #1

(A) the equation used for this purpose is Q = mcdt

Where

m = mass of water in the calorimeter

c = specific heat capacity of water

dt = change in temperature = final - initial

(B) The amount of heat lost by the metal = heat gained by the water in the calorimeter

m'c'dt' = mcdt

Where

m = mass of water in the calorimeter

c = specific heat capacity of water

dt = change in temperature = final - initial

m' = mass of metal

c' = specific heat capacity of metal

dt' = change in temperature of metal = initial - final

(C) The heat lost by the meatl , Q = m'c'dt'

From this we calculate the specific heat of the metal , c' = Q / (m'dt')

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A. Calculate ∆T for the water (Tfinal – Tinitial).
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Balance temperature: 27ºC
Initial water temperature: 23ºC
Initial temperature of the metal part: 68ºC
Mass of the metal part: 193 grams
Mass of the empty calorimeter: 110 grams
Mass of the water inside the calorimeter: 250 grams
Specific heat of water: 4.19 J / gºC
Specific heat of the calorimeter (aluminum): 0.90 J / gºC
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A
47.5 block of an unknown metal is heated in a hot water bath to 100
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