Question

Please Answer ALL THREE questions

1)Determine the molar mass of Mn(ClO4)3.

2)53.5 mol of P4O10 contains how many moles of P?

3)How many moles of Al(CN)3 are in 169 g of the compound?

Answer 1

1)

Molar mass of Mn(ClO4)3,

MM = 1*MM(Mn) + 3*MM(Cl) + 12*MM(O)

= 1*54.94 + 3*35.45 + 12*16.0

= 353.29 g/mol

Answer: 353.29 g/mol

2)

1 molecule of P4O10 has 4 atoms of P

So,

moles of P = 4*moles of P4O10

= 4*53.5 moles

= 214 moles

Answer: 214 moles

3)

Molar mass of Al(CN)3,

MM = 1*MM(Al) + 3*MM(C) + 3*MM(N)

= 1*26.98 + 3*12.01 + 3*14.01

= 105.04 g/mol

mass(Al(CN)3)= 169 g

number of mol of Al(CN)3,

n = mass of Al(CN)3/molar mass of Al(CN)3

=(169.0 g)/(105.04 g/mol)

= 1.61 mol

Answer: 1.61 mol